Dúvida quanto ao BASH

trap: trap [-lp] [[arg] signal_spec ...]
Trap signals and other events.

Defines and activates handlers to be run when the shell receives signals
or other conditions.

ARG is a command to be read and executed when the shell receives the
signal(s) SIGNAL_SPEC. If ARG is absent (and a single SIGNAL_SPEC
is supplied) or `-', each specified signal is reset to its original
value. If ARG is the null string each SIGNAL_SPEC is ignored by the
shell and by the commands it invokes.

If a SIGNAL_SPEC is EXIT (0) ARG is executed on exit from the shell. If
a SIGNAL_SPEC is DEBUG, ARG is executed before every simple command.

If no arguments are supplied, trap prints the list of commands associated
with each signal.

Options:
-l print a list of signal names and their corresponding numbers
-p display the trap commands associated with each SIGNAL_SPEC

Each SIGNAL_SPEC is either a signal name in <signal.h> or a signal number.
Signal names are case insensitive and the SIG prefix is optional. A
signal may be sent to the shell with "kill -signal $$".

Exit Status:
Returns success unless a SIGSPEC is invalid or an invalid option is given.

MaicoREC escreveu:

Certo
tenho o seguinte código

#!/bin/bash
i=0
while true; do
(($i==0)) && echo "entrou"
((i++))
sleep 800
done

ele faz um loop "infinito" no bash, é isso que eu quero, isso eu ja fiz, sendo que quando o user da control + c, ele abre o bash normalmente, quero que quando o user der control + c, ele deslogue do sistema, ou seja exit, como ficaria meu codigo?

#!/bin/bash

function _loop()

{

    while :

    do

       sleep 0.8s

    done

    return 2

}

_loop || exit